Railway Mock Test-01 

Railway RRB NTPC Important Mock Test-01-Held on 27-10-2013:(RRB NTPC) vacancy को ध्यन मे रखते हुई आज हमारी Team-www.allgovtjobsindia.in आप के रेलवे के Exam Pattern को धयान मे रखते हुई आप के एग्जाम की अच्छी सफलता के लिए – RRB NTPC Importan Mock Test ले आये है जो कि आप की परीक्षा को पास करने मे बहुत ही लाभदायक सिद्ध होगी आशा है आप लोगो को हमारा ये Railway Mock Test – जरुर पसंद आये गया-

Vacancy Details : रेलवे भर्ती बोर्ड(RRB NTPC) : प्रिय विद्यार्थियों, आप लोगो को पता ही होगा की आरआरबी एनटीपीसी (RRB NTPC) द्वारा कुल 1 लाख 30 हजार  भर्ती का आवदेन निकला गया है, जिसकी भर्ती प्रक्रिया (1 मार्च, 2019) से विभिन पदों के लिए आवदेन लिये जाएगे-  जिसमे नॉन टेक्निकल पॉपुलर कैटेगरी (एनटीपीसी) के लिए 30 हजार पद रखे गये है  वही (एनटीपीसी) : पैरामेडिकल स्टाफ, मंत्रालय और आइसोलेटिड कैटेगरी होगी –

नॉन टेक्नीकल श्रेणी: पदों के लिए इन कैटेगरी को रखा गया है- जिसमे 1 लाख पद के लिए vacancy भरे जायेगे  –टिकट जूनियर क्लर्क सह टाइपिंस्ट, ट्रेन्स क्लर्क, अकाउंट्स क्लर्क सह टाइपिस्ट, गुड्स गार्ड, सीनियर कमर्शियल सह टिकट क्लर्क, ट्रैफिक असिस्टेंट, सीनियर क्लर्क सह टाइपिस्ट, कमर्शियल अप्रेंटिस, टीटीई, असिस्टेंट स्टेशन मास्टर आदि के कैटेगरी की भर्ती की जाएगी –

Topic: Railway Mock Test Ticket Collector (TC), Commercial Clerk (CC),

Subject: Maths / Reasoning

Questions: 10 Objective Type Question
Time Allowed: 06 Minutes
Helpful for: Non-Technical –Junior Clerk Cum Typist, Commercial Apprentice, Senior Clerk cum typist, Account Clerk Cum Typist, Trains Clerk, Traffic Assistant, Goods Guard, Senior Commercial,  Junior Accountant Cum Typist, Commercial Apprentice, Station Master, Commercial Cum Ticket Clerk. Para Medical: Staff Nurse, Health & Malaria Inspector, Pharmacist, ECG Tech, Lab Assistant, Lab Supt. Ministerial and Isolated: Assistant Pointsman, Steno, Grade IV, Helper/Assistant, Chief Law Assistant, Junior Translator(Hindi), Track Maintainer. Level 1 RRC – Track Maintainer, Grade IV, Helper/Assistant, Assistant Pointsman,  Level-1 Posts

RRB ALLAHABAD TC & CC EXAM -27.10.2013

Time limit: 0

Quiz-summary

0 of 10 questions completed

Questions:

1. 1
2. 2
3. 3
4. 4
5. 5
6. 6
7. 7
8. 8
9. 9
10. 10

Information

welcom

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

Average score
Your score

Categories

1. Railway Quiz 0%

• Welcom

Your result has been entered into leaderboard

Loading

Name: E-Mail:

Captcha:

1. 1
2. 2
3. 3
4. 4
5. 5
6. 6
7. 7
8. 8
9. 9
10. 10

1. Answered
2. Review

1. Question 1 of 10

   1. Question

   1. 22 boys are standing in front of kunal in a queue. 12 boys are standing to the back of Rohit in the same queue. If total number of boys is 30 then the number of boys standing in between kunal and Rohit is –

   • 3
   • 4
   • 6
   • 5
   Correct
   

   

   Incorrect
   

   
2. Question 2 of 10

   2. Question

   2. In the following sequence of alphabets

   a a b a b a a b a b a a a b b a b a b b a a a a

   the number of a’s in between 7th a from left and 7th a from right is –

   • 1
   • 0
   • 3
   • 2
   Correct
   

   

   Incorrect
   

   
3. Question 3 of 10

   3. Question

   If A stands for ‘+’, B stands for ‘–’, C stands for ‘×’ and D for ‘÷’ ‘then 1/2A 1/3B 1/4C 1/5D 1/6 =

   • 0
   • 17/30
   • 8/15
   • 13/15
   Correct
   

   

   Incorrect
   

   
4. Question 4 of 10

   4. Question

   4. If 1st July, 1977 was a Friday then 1st July 1970 was a–

    

   • Wednesday
   • Thursday
   • Sunday
   • Tuesday 
   Correct
   

   Answer: 1

   Explanation: 

   Number of odd days upto 1st July 1977 :

   Number of odd days in January 1977=3

   Number of odd days in February 1977=0

   Number of odd days in March 1977=3

   Number of odd days in April 1977=2

   Number of odd days in May 1977=3

   Number of odd days in June 1977 = 2
   —————
   13 odd days

   1976 was a leap year, so number of odd days=2

   In 1975 number of odd day= 1
   In 1974 number of odd days = 1
   In 1973 number of odd days = 1
   In 1972 was the leap year,so number of odd days = 2
   In 1971,number of odd days = 1
   Number of odd days in 1970 from December to 1st July
   = 3 + 2 + 3 + 2 + 3 + 3 = 16
   Total number of odd days
   = 13 + 8 + 16 = 37, i.e 2 odd days

   Therefore, 1st July, 1970 was two days before Friday, i.e, Wednesday

   Incorrect
   

   Answer: 1

   Explanation: 

   Number of odd days upto 1st July 1977 :

   Number of odd days in January 1977=3

   Number of odd days in February 1977=0

   Number of odd days in March 1977=3

   Number of odd days in April 1977=2

   Number of odd days in May 1977=3

   Number of odd days in June 1977 = 2
   —————
   13 odd days

   1976 was a leap year, so number of odd days=2

   In 1975 number of odd day= 1
   In 1974 number of odd days = 1
   In 1973 number of odd days = 1
   In 1972 was the leap year,so number of odd days = 2
   In 1971,number of odd days = 1
   Number of odd days in 1970 from December to 1st July
   = 3 + 2 + 3 + 2 + 3 + 3 = 16
   Total number of odd days
   = 13 + 8 + 16 = 37, i.e 2 odd days

   Therefore, 1st July, 1970 was two days before Friday, i.e, Wednesday
5. Question 5 of 10

   5. Question

   If ‘A + B’ stands for ‘A is the father of B’, ‘A – B’ stands for ‘A is the brother of B’, ‘A × B’ stands for ‘A is the wife of B’ and ‘A ÷ B’ stands for ‘A is the sister of B’ then ‘P + Q ÷ R’ means–  

   • P is the father of R
   • R is the sister of P
   • R may be father of P
   • R is sister of Q
   Correct
   

   Answer: 1

   Explanation:

   P + Q -> P is father of Q.

   Q ÷ R -> Q is the sister of R.

   Therefor, P is the father of Q and R.

   Incorrect
   

   Answer: 1

   Explanation:

   P + Q -> P is father of Q.

   Q ÷ R -> Q is the sister of R.

   Therefor, P is the father of Q and R.
6. Question 6 of 10

   6. Question

   In a certain code language ‘278’ means ‘run very fast’, ‘853’ means ‘come back fast’ and ‘376’ means ‘run and come’ then ‘back be represented by the digit

   • 3
   • 7
   • 5
   • 6
   Correct
   

   

   Incorrect
   

   
7. Question 7 of 10

   7. Question

   If X is a player then X must be stout. This statement can be deduced from

   • Only players are stout
   • None but the stout men are players
   • All stout men are players
   • Some players are stout
   Correct
   

   Answer- 4

   Explanation- The statement implies that all player are stout. If all players are stout, them some player must be stout.

    

   Incorrect
   

   Answer- 4

   Explanation- The statement implies that all player are stout. If all players are stout, them some player must be stout.

    
8. Question 8 of 10

   8. Question

   Find the odd one out.

   • Kitchen
   • Psychology
   • Campaign
   • Utensil
   Correct
   

   Answer- 3

   Campaign is used as both verbs and Noun. All other words are Nouns.

   Incorrect
   
9. Question 9 of 10

   9. Question

   Natural : Artificial : : Spontaneous : ?

   • Calculated
   • Impromptu
   • Instinctive
   • Free of all
   Correct
   

   Answer – 1

   Natural is the antonym of Artificial. Similarly, Spontaneous is the antonym of Calculated.

   Incorrect
   

   Answer – 1

   Natural is the antonym of Artificial. Similarly, Spontaneous is the antonym of Calculated.
10. Question 10 of 10

    10. Question

    The sum of all the natural number between 301 and 501 ( including 301 and 501) which are divisible by 7 is

    • 11277
    • 12571
    • 15171
    • 11571
    Correct
    

    Answer- 4

    Explanations- The smallest number = 301

    The largest number = 497,

    Common difference = d = 7

     

    tn=a + (n-1) d

    => 497 = 301 + (n – 1) x 7

    => (n – 1 = 196 ÷ 7 = 28

    => n – 1 = 497 – 301 = 196

    => n = 28 + 1 = 29

    Required sum

     

    = n/2 (first term + last term)

    = 29/2 ( 301 + 497 )

     

    = 29 x 798/2  = 11571

    Incorrect
    

    Answer- 4

    Explanations- The smallest number = 301

    The largest number = 497,

    Common difference = d = 7

     

    tn=a + (n-1) d

    => 497 = 301 + (n – 1) x 7

    => (n – 1 = 196 ÷ 7 = 28

    => n – 1 = 497 – 301 = 196

    => n = 28 + 1 = 29

    Required sum

     

    = n/2 (first term + last term)

    = 29/2 ( 301 + 497 )

     

    = 29 x 798/2  = 11571

नोट: कृप्या जादा से जादा Mock Test देने का प्रयास करें – अगर पसंद आये तो आपने मित्रो को जरुर बाताये या शेयर करे “धन्यवाद !!